Week+of+03-15-10

Section 1: Thought Question of the Week

 Fill in the missing part of this sequence:

 A, E, ..., NA, AO

 Clues:  1. The numbers matter.  2. Large scale.

Name: Brianna Behrens  Date: 3/19/10  Type of Posting: 1  Posting: This question was really hard, and I'm not sure if my answer is right. Considering that the numbers matter, the letters would translate into "1, 5,..., 15, 16." You get the 15 from adding 14, which is the N, and 1, which is the A; the same goes for the 16. I thought that the missing part of the sequence could be 6; seeing that 1 and 5 is fifteen (not by adding them), I thought 6 could make sense: 1 and 6; 16. This was the only logical explanation I could think for the missing number.

 Sections 2 and 3: Questions on Homework //Please post any responses to homework questions right below the posting that you are answering.//

 // ** Name: ** Lauren Thau // // **Date:** 3/15/10 // <span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 14px;">//<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 13px; font-style: normal; line-height: 19px;"> ** Type of posting: ** 2 // <span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 14px;">//<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-style: normal; line-height: 23px;"> ** Posting: Hi everyone. I am really confused with number 15 on the chapter 8 review. I know that i first need to distribute the negative sign but do I have to combine like terms or do foil. Thanks you. ** //

**Name:** Jon Libock **Date:** 3/16/10 **Type of posting:** 3 **Posting: Well Morgan, after you distribute the negative sign you can take away the parentheses and combine like terms. Hope I helped.**

<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Name: ** Jordan Abend <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Date:** 3/17/10 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Type of posting: ** 2 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Posting: ** Hello everyone. How are you doing? I'm having trouble with # 59 on p. 478. The monomials are 28a^2, 63a^3b^2, 91b^3. Since 28, 63, and 91 have a GCF of 1 and the exponents don't have a GCF, I am unsure of what to put as my answer. Do I put no GCF or no solution. Help would be appreciated. Have a great night everybody.

Name: Matt McGee Date 3/21/10 Type of posting: response to Jordan Hey Jordan, i believe you would put 1 as your GCF, i am unsure if my answer is correct, if any one could help it would be great.

====<span style="color: #808080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Name: Selma Zayer <span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Date: 3/18/10 <span style="color: #404040; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Type of posting: 2 <span style="color: #008000; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Posting: For the 9-2 worksheet that was homework tonight, I am having trouble with number 10. The problem is 3p^2q^2 + 6pq + p. I do not get if I put a q with my GCF because the last p does not have a q. So would I include a q? Thanks for the help. <span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Name: Brian Horn Date: 3/18/10 Type of Posting: 3 Posting: Hey Selma, for that problem you don't have to include the q. On of the factors doesn't have q so it shouldn't be included in the GCF. Hope this helps! ====

<span style="color: #ff007c; font-family: 'Comic Sans MS',cursive;"> ** Type of posting: ** 2
==== <span style="color: #ff007c; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: ** Hi everyone! I'm having trouble with #17 on 9-2 skills practice. I'm supposed to factor 6t^2-4t-3t+2, but I got 2t(3t-2) (-3t+2). How do I continue if the numbers inside the parenthesis are different? Please Help! <span style="font-family: ComicSansMS,helvetica,sans-serif; font-size: 21px; line-height: 32px;">**Name:** Max Mongiello  ==== **Date:** 3/18/10 **Type of posting:** 2 **Posting: Hello world! I am stuck on number 8 for tonights hw on Skills Practice 9-2, the problem is a^2b^2+a. So far I have a(ab^2+1). This is the first problem I have done with that format and I am wondering if I am correct, if not please help me. Thanks and have a great night!**

Name: **Nick Rizzo** Date: **3/18/10** Type of posting: **2** **Posting: Hey guys what's up :) I am doing the homework worksheet we got during class. I was doing number 15 and was unsure. It reads 2s2 + 2s + 3s + 3. I am not sure if I did it right so I wanted to check. This is what I did. I grouped the (2s2 + 2s) and then I grouped (3s + 3) Then I factored each grouping. For the first one I got 2s(s + 1) and 3(s + 1) Then I got (s + 1) (2s =3) as my answer. I think this is correct, is it? Thanks for your time :)**

**<span style="color: #14c814; font-family: Georgia,serif;">Name: Remzi Tonuzi ** **<span style="color: #14c814; font-family: Georgia,serif;"> Date: 3/21/10 ** **<span style="color: #14c814; font-family: Georgia,serif;"> Type of Posting: 3 ** **<span style="color: #14c814; font-family: Georgia,serif;"> Posting: ** **<span style="color: #14c814; font-family: Georgia,serif;"> Hey Nick, you're answer is almost correct. You wrote (s+1) (2s =3). I got (s+1) (2s+3). So you just messed up your signs but otherwise, you did a good job. Hope that helped. **

** Name: Kennedy Clifford ** ** Date: 3-18-10 ** ** Post: 2 ** ** Hey guys. On tonight’s homework, Skills Practice 9-2, I was having trouble on number 17. The problem is 6t2 -4t – 3t +2. I grouped these and got (6t2-4t)-(3t+2). I know I have to factor them individually, so for the first one I got 2t(3t-2), but the second one is where I am confused. I am confused about the subtraction sign. Should it be 1(-3t+2) because I have to add a line, change the sign for the subtraction? I am pretty sure that is not correct, so <span style="color: #36a92d; font-family: 'Comic Sans MS',cursive; font-size: 81%;">can someone help me factor the second part of this problem? **

**<span style="color: #36a92d; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Name: Francesca Pucciarelli ** **<span style="color: #36a92d; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Date: 3-18-10 ** **<span style="color: #36a92d; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Type of posting: 3 ** **<span style="color: #36a92d; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Posting: Hey everybody! Nick, I checked my work and I got something slightly different than you. After factoring both we both got 2s(s+1)+3(s+1), but after that you group the terms on the outside and the inside together, so you should get (2s+3)(s+1). I am pretty sure I did it right, but if i didn't it would be great if someone could tell me. I hope this helped:) **

**<span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;">Name: Anna Behnke ** **<span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Date: 3-18-10 ** **<span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Type of posting: 3 ** **<span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Posting: Hey guys! Francesca, I looked over your work and everything is right, except for one thing. For your answer you got: <span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 81%;">(2s+3)(s+1) <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;">. Instead the answer should have been <span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 81%;">(s+1) (2s+3) <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> because the Greatest Common Factor should go before the left over variables/ numbers. =D <span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 81%;">G <span style="color: #ff4c00; font-family: 'Comic Sans MS',cursive; font-size: 81%;">O <span style="color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 81%;">M <span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 81%;">A <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;">T <span style="color: #020897; font-family: 'Comic Sans MS',cursive; font-size: 81%;">H <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;">!!! **

**<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;">Name: Marissa Moschella ** **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Date: 3-18-10 ** **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Type of posting: 2 ** **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 81%;"> Posting: Hey! ON the skills practice 9-2 for tonight's homework i was having some trouble with number 17. My final answer that I came up with was 2t(3t-2)+(-3t+2). Can someone tell me if that was correct? **

<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 17px; line-height: 25px;"> **Name: Juliet Altmann** <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 17px; line-height: 25px;"> **Date: 3-19-10** <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 17px; line-height: 25px;"> **Type of posting: 2** <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 17px; line-height: 25px;"> **Posting: Hey everyone! In response to Marissa you are missing the 1 before (-3t +2), you have to remember that place value. Your answer is also not correct because both of your terms in parenthesis are not the same.**

<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Name: Hailey Persoentte <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Date: 3-18-10 <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Type of pposting: 3? <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Posting: Hello everyone.. Im responding to Marissa. yes, your final answer is correct! Whata genius.

<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Name: Drew Mann <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Date: 3/18/10 <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Type of Posting: 2 <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;"> Posting: <span style="color: #c14eb2; font-family: 'Comic Sans MS',cursive;">When factoring a polynomial and there are variables with exponents, how do you factor them. If it a to the 3rd does it stay like that or does it become AxAxA.

Name: Allison Rosenthal Date: 3-21-10 Type of Posting: 3 Posting: Hi, im relpying to drews question. When you are factoring a polnomial and there are variables, once you find your GCF you take out, or subtract the the number or variables from your GCF from the original polynomial, but before you find the GCF if it is a polynomial you must group.