Week+of+04-05-10

Section 1: Thought Question of the Week

 Subject: Wild Inventions

 Lucky for her employers, along with being an executive secretary who took pride in her work, she was also an artist. What was her invention?

 Clues:  1. She did not participate in any marketing for her employers.  2. She did not create an artistic display.

 **Name: Marissa Moschella**  **Date: 4** -11-10  **Type of posting: 1**  **Post: Personally, I think this woman invented the pencil. Since she is a secretary, so her profession requires a lot of writing. This is why I believe she grew tired of dipping her quill pen in ink so she invented the pencil which writes much longer on one sharpening!**

 ** Name: Brittany Hand ** ** Date: 4 ** -11-10 ** Type of posting: 1 ** ** Post: ** <span style="color: #ff00ff; font-family: arial,helvetica,sans-serif; font-size: 17px; line-height: 19px;">She created the computer. It is hard work and its not really an artistic display.

<span style="color: #8200ff; font-family: arial,helvetica,sans-serif; font-size: 13px; line-height: 19px;"> ** Name: Max Mongiello ** <span style="color: #8200ff; font-family: arial,helvetica,sans-serif; font-size: 13px; line-height: 19px;">** Date: 4 ** <span style="color: #ff00ff; font-family: arial,helvetica,sans-serif; font-size: 17px; line-height: 19px;">-6-10 <span style="color: #8200ff; font-family: arial,helvetica,sans-serif; font-size: 13px; line-height: 19px;">** Type of posting: 1 ** <span style="color: #8200ff; font-family: arial,helvetica,sans-serif; font-size: 13px; line-height: 19px;">** Post: ** <span style="color: #ff00ff; font-family: arial,helvetica,sans-serif; font-size: 17px; line-height: 19px;">Hello class, I think that her invention was the **roller skate** in 1700's. It is in my opinion that a hard working secretary like herself would have been able to gain access to the information and materials that would have made it possible. Thank you hope everyone enjoyed break!

**Name: Jon Libock** **Date:** 4/7/10 **Type of posting: 1** **Post: She was a con artist that would cheat her employees. Her invention was lying.**

Name: Jeff Schecter Date: 4/10/10 Type of posting: 1 Posting: I agree with Jon. She was a con artist who invented lying. Being a con artist is probably very hard work. Also there is no display lying.

<span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 17px;">Sections 2 and 3: Questions on Homework <span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 14px;">//Please post any responses to homework questions right below the posting that you are answering.//

<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Name: ** Katie Brinskele <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Date:** 4/5/10 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Type of posting: ** 2 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Posting: ** Hey Guys! For the homework, I had some trouble on number 12. The problem was <span style="color: #e51515; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">9/25m^2= 121. <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> We haven't done these problems using fractions yet so I tried my best. First I set it equal to 0 and I got <span style="color: #e81111; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">9/25m^2-121=0 <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">. Then I didn't really no where to go from there because I was confused on what I was supposed to do with the 9/25 because we never went into fractions. If anyone could help me it would be much appreciated. Thank you!

===<span style="color: #9700ff; font-family: 'Comic Sans MS',cursive;">**<span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 14px;">Hey Guys. For tonight's homework, I was confused with Number 10. If there isn't a GCF between 49 and 81 would the answer be PRIME? ** ===

<span style="color: #9700ff; font-family: 'Comic Sans MS',cursive;">**<span style="color: #1cff00; font-family: 'Comic Sans MS',cursive; font-size: 14px;">Please let me know. Thanks :) **

 * Name: ** Kennedy Clifford
 * Date: ** 4-6-10
 * Type of posting: ** 2 response to Paige
 * Post: ** Hey Paige. First, for number 10 you need to ** subtract 49 from both sides ** . This would leave you with ** 81x2-49=0. ** Then you have to ask yourself **“what is the square route of 81?”** and **“what is the square route of 49.”** **The square root of 81 is 9 and the square root of 49 is 7** . After doing that, you would get **(9x-7)(9x+7)=0** (one of the 7’s is positive and one is negative because the original problem has a -49 in it.) You then need to **set each factor equal to 0** and you would get ** 9x-7=0 and 9x+7=0 ** . From here just **solve each for X** and those would be your answer.

<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Name: ** Jordan Abend <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Date:** 4/7/10 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Type of posting: ** 2 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive;"> ** Posting: ** Hello everybody! How are you doing today. I have a question about last night's homework. For number 11 am I supposed to subtract the 25 and make 1/4x^2-25=0. Then what do I do from there? I am really confused about factoring polynomials. An answer would be much appreciated and have a good day Pascack Hills.

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">**Name:** Corey Pic <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Date:** 4/7/10 <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Type of Posting:** 2 <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Posting:** Hey everyone, how is it going? For tonight's homework, I had trouble doing number 7. The problem is ** 98x^2- 200y^2. I know that I have to find a GCF to factor out, this is what I have so far 2(49x^2-100y^2) but I do not know what to do next, please help! **

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Name: Lerna Girgin ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: 4/7/10 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 2 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: Tonight's homework, number 9 I am not sure how to proceed after I write out 9x^2 - 6x + 1 = 9. I do not understand how I am supposed to get it into the position of grouping. **

<span style="color: #800000; font-family: 'Comic Sans MS',cursive; font-size: 16px;">** Date: 4/7/10 **
====<span style="color: #800000; font-family: 'Comic Sans MS',cursive; font-size: 16px;"><span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 2 ** (Lerna's question) ==== ====<span style="color: #800000; font-family: 'Comic Sans MS',cursive; font-size: 16px;">Posting: Hi! In this equation, there is no perfect square. Now you need to multiply the 9 and the 1 and find factors of 9 that add up to -6. The factors are -3 and -3. Then you get 9x^2-3x+ -3x+1=0. Then you put it in grouping and find the GCf. Eventually you will get x=1/3 ====

<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Name: ** <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> Morgan Thau <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: ** <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> 4/7/09 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of posting: ** <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> 2 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: ** <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Hey everyone. I also really had trouble with number 9 on the homework assignment. Here is the problem: <span style="color: #0057ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">9x^2 - 6x + 1 = 9 <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">. <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px;">I know that I am supposed to ask myself <span style="font-family: 'Comic Sans MS',cursive; font-size: 16px;">** Is this a perfect square trinomial? ** <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px;">So far, I have (9x-1)^2. Any thoughts on where I should go from here? Thanks so much!

<span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Name: ** <span style="color: #0057ff; font-family: arial,helvetica,sans-serif; font-size: 13px; font-weight: normal; line-height: 19px;"> Lauren Thau <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Date: ** <span style="color: #0057ff; font-family: arial,helvetica,sans-serif; font-size: 13px; font-weight: normal; line-height: 19px;"> 4/7/09 <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Type of posting: ** <span style="color: #0057ff; font-family: arial,helvetica,sans-serif; font-size: 13px; font-weight: normal; line-height: 19px;"> 3 <span style="color: #ff00e7; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Posting: Hey Morgan. For number 9 on the homework your very close! Good try though! Instead of doing (9x-1)^2 you need to do (3x-1)^2. This is because you need to find the square root of the 9 and 1. Don't worry though you'll get it next time. If you have any problems, you know where to find me!! **

=<span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 16px;">** Selma Zayer ** = =<span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 16px;">** Date: 4/7/10 ** = =<span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 16px;">** Type of posting: 2 ** = = ** Posting: Hello everyone. I do not comprehend anything on the homework tonight. I don't get how to do the problems. Help would be greatly appreciated. ** = Name: Hailey Personette Date: 4/8/10 Type of posting: 3 Posting: Hey Selma! Umm, well you didn't give any particular problems on what your having trouble with. So, I'll do factoring polynomials. If the problem is, for exampple:36x^2-12x+1.. you should first make sure they are perfect squares. And pull them out, so 36 is six and 1 is well one.Then you want to double it. So 6x X 2= 12x .. And see how the middle number is 12x. So yah you know its correct. The answer is (6x-1). I got the minus because in the orginal problem, the 12 is negative. Hope i helped and didn't confuse anyone! Name: **Nick Rizzo** Date: 4**/7/10** Type of posting: **2** Posting: Hey guys what’s up? :) I was doing the homework last night and I was confused about a problem. For number 7 I was a little confused. I tried finding the square roots for 98 and 200 but they were not perfect squares. I put it, as prime because there were no perfect squares and I don’t think there was anyway to do it. Maybe I could have factored but I am not sure. I could be wrong but what did you guys get? Thanks for your time :)

<span style="font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">**<span style="font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> Name: ** <span style="color: #ff5900; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> Deniz Piatt <span style="font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">**<span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">Date: ** <span style="color: #ff0000; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> 4/7/09 <span style="font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Type of posting: ** 2 <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: What's up guys? How was everyones break? I got some trouble on #12 on homework! I know you have to solve, but it equals -121, I only know how to solve for zero. I know you have to move it with the other numbers, but I'm confused on if I have to change certain signs. Can anyone help? ** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Thank you, ** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** From Your Class President, ** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Deniz E. Piatt **

<span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Name:Anna Behnke** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Date:4/8/10** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Type of Posting: 2 (response to Deniz's question)** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> **Posting: Hey, Deniz! I have an easy solution to your question. The equation is: x2+22x=-121. All you have to do is add the -121 to the other side of the equals sign and set the equation equal to 0. After that step the problem should look like: x2+22x+121=0. Now you are set to finish the problem! Hope I helped! =]**

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"> ** Name: Sammy Rosen ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: 4/8/10 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 2 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: ** <span style="color: #2be92b; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;"><span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Hey guys! I am doing the homework and I'm on number 8. The problem is 5y^2-90. The first line I have is 5(y^2-18). I was wondering if this is the answer because the other day Ms. Garruto said that no problem should never have only one line. So, is the answer to number 8 ** 5(y^2-18)?

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;"> Name: Remzi Tonuzi <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;"> Date: 4/9/10 <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;"> Type of Posting: 2 <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;"> Posting: For the homework last night, I don't understand how to do number 9. <span style="color: #0036ff; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;">24x^3 - 78x^2 + 45x. <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; font-weight: normal; line-height: 23px;">How would I solve this problem with uneven exponents? = =

//Name: Jake Waldron// //Date:4/9/10// //Type of Posting: 2 (response to Remzi's question)// //Posting: Hey Remzi all you have to do is group the factors and then solve it as if it were a normal problem.//

//Name: Drew Mann// //Date:4/9/10// //Type of Posting:2// //Posting: If there is a problem like 3w^2+6w-24=0. When your finding the GCF and you get 3(w^2+3w-8)=0, how do you find the factors equal to zero.//

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Name: Will Calderone ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: 4/9/10 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 2 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: How would i go about solving this problem, 18y^2-48y+32 if you could help that would be nice. Would i have to group it? **


 * Name: ** Brian Horn
 * Date: ** 4-11-10
 * Type of posting: ** 3 response to William above
 * Post: ** Will at first you have to find the GCF which would be 2. Then you multiply the first and last number and find two numbers that when multiplied equal it and the difference is the middle number. Then just follow the steps. No you don't have to group. Hope this helps.

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Name: Julian Gallardo ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: 4/9/10 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 3 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: Will you would have to first see if there is a GCf and if it is a Perfect Trinomial. But for this problem you have to take the first number and the last (18y^2 and 32). You multiply them together and then with the number that you get you have to find two factors that add up to 48. With those group them and you will be done! **

<span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Name: Allison Rosenthal ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Date: 4/12/10 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Type of Posting: 3 ** <span style="color: #000080; font-family: 'Comic Sans MS',cursive; font-size: 16px; line-height: 23px;">** Posting: Hi class, sorry this is late, but its better late then never! On the homework i have a question about number 11. on page 9-3. How do you factor that when there is no GCF, or Diffrence of two squares? **